获取两个数组的交集或者差集
2024-05-08 本文已影响0人
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let arr1= [...list1].filter(x => [...list2].some(y => y == x.name)); 交集
let arr2= [...list1].filter(x => [...list2].every(y => y != x.name)); 差集
let arr1= [...list1].filter(x => [...list2].some(y => y == x.name)); 交集
let arr2= [...list1].filter(x => [...list2].every(y => y != x.name)); 差集