2018-06-15 LeetCode53
2018-06-15 本文已影响0人
Betrayer丶
题目描述
我的解法
O(n)的复杂度,sum[i]=max{sum[i-1] + a[i], a[i]}
class Solution:
def maxSubArray(self, nums):
sums=nums[0]
s=0
for i in range(len(nums)):
if s > 0:
s=s+nums[i]
else:
s=nums[i]
if sums < s:
sums=s
return sums
最优解法
class Solution:
def maxSubArray(self, nums):
sum = 0
max = nums[0]
for index in range(len(nums)):
if sum < 0:
sum = 0
sum += nums[index]
if sum > max:
max = sum
return max