Algorithm

LeetCode #1. Two Sum

2017-06-07  本文已影响0人  匠_心

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

Solution:

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> result{};
        for(int i=0;i<nums.size();++i)
        {
            for(int j=i+1;j<nums.size();++j)
            {
                if(nums[i]+nums[j]==target)
                {
                    result.push_back(i);
                    result.push_back(j);
                }
            }
        }
        return result;
    }
};
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