PyQt5使用多线程防止卡死
2021-01-21 本文已影响0人
yichen_china
下面将这两个循环使用多线程来写,在PyQT5中,使用QThread
from PyQt5.Qt import (QApplication, QWidget, QPushButton,
QThread)
import sys
import time
# 继承QThread
class Thread_1(QThread): # 线程1
def __init__(self):
super().__init__()
def run(self):
values = [1, 2, 3, 4, 5]
for i in values:
print(i)
time.sleep(0.5) # 休眠
class Thread_2(QThread): # 线程2
def __init__(self):
super().__init__()
def run(self):
values = ["a", "b", "c", "d", "e"]
for i in values:
print(i)
time.sleep(0.5)
再次执行文件,不管我们点击哪个按钮,点击多少次
在控制台会立刻打印内容
且窗口不会出现卡顿,假死。
按钮1使用线程锁,按钮2使用信号
注意两者的区别,按钮1可以无限点击,按钮2在点击之后,开启循环,按钮呈不可点击状态,只有当循环结束后,才能被再次点击
from PyQt5.Qt import (QApplication, QWidget, QPushButton,
QThread,QMutex,pyqtSignal)
import sys
import time
qmut_1 = QMutex() # 创建线程锁
qmut_2 = QMutex()
# 继承QThread
class Thread_1(QThread): # 线程1
def __init__(self):
super().__init__()
def run(self):
qmut_1.lock() # 加锁
values = [1, 2, 3, 4, 5]
for i in values:
print(i)
time.sleep(0.5) # 休眠
qmut_1.unlock() # 解锁
class Thread_2(QThread): # 线程2
_signal =pyqtSignal()
def __init__(self):
super().__init__()
def run(self):
# qmut_2.lock() # 加锁
values = ["a", "b", "c", "d", "e"]
for i in values:
print(i)
time.sleep(0.5)
# qmut_2.unlock() # 解锁
self._signal.emit()
class MyWin(QWidget):
def __init__(self):
super().__init__()
# 按钮初始化
self.btn_1 = QPushButton('按钮1', self)
self.btn_1.move(120, 80)
self.btn_1.clicked.connect(self.click_1) # 绑定槽函数
self.btn_2 = QPushButton('按钮2', self)
self.btn_2.move(120, 120)
self.btn_2.clicked.connect(self.click_2) # 绑定槽函数
def click_1(self):
self.thread_1 = Thread_1() # 创建线程
self.thread_1.start() # 开始线程
def click_2(self):
self.btn_2.setEnabled(False)
self.thread_2 = Thread_2()
self.thread_2._signal.connect(self.set_btn)
self.thread_2.start()
def set_btn(self):
self.btn_2.setEnabled(True)
if __name__ == "__main__":
app = QApplication(sys.argv)
myshow = MyWin()
myshow.show()
sys.exit(app.exec_())