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Linux基础 - shell数组

2018-01-25  本文已影响49人  菩提老鹰

摘要

数组的特性就是一组数据类型相同的集合,虽然shell是弱类型,但是我们也可以将其数组分为数据类型的数组字符串类型的数组两类
shell的数组元素之间用空格分隔开


数组操作

假设有以下两个数组

array1=(1 2 3 4 5 6)
array2=("James" "Colin" "Harry")
root@pts/1 $ echo $array1
1
root@pts/1 $ echo $array2
James
root@pts/1 $ echo ${array1[2]}
3
root@pts/1 $ echo ${array2[1]}
Colin

## 获取全部元素
root@pts/1 $ echo ${array2[*]}
James Colin Harry
root@pts/1 $ echo ${array2[@]}
James Colin Harry
root@pts/1 $ echo ${#array1[@]}
6
root@pts/1 $ echo ${#array2[*]}
3
root@pts/1 $ for item in ${array2[@]}
> do
>     echo "The name is ${item}"
> done
The name is James
The name is Colin
The name is Harry

格式:数组名[下标]=值,如果下标不存在,则新增数组元素; 下标已有,则覆盖数组元素值

root@pts/1 $ array1[2]=18
root@pts/1 $ echo ${array1[*]}
1 2 18 4 5 6

root@pts/1 $ array2[4]="Betty"
root@pts/1 $ echo ${array2[*]}
James Colin Harry Betty

格式:${数组名[*或@]:起始位:长度},截取部分数组,返回字符串,中间用空格分隔;将结果使用(),则得到新的切片数组

root@pts/1 $ echo ${array2[*]}
James Colin Harry Betty
root@pts/1 $ echo ${array2[*]:1:3}
Colin Harry Betty

root@pts/1 $ array3=(${array2[*]:1:2})
ks-devops [~] 2018-01-25 20:30:16
root@pts/1 $ echo ${array3[@]}
Colin Harry

格式:${数组名[*或@]/查找字符/替换字符}, 不会修改原数组;如需修改的数组,将结果使用“()”赋给新数组

root@pts/1 $ echo ${array2[*]}
James Colin Harry Betty
root@pts/1 $ echo ${array2[*]/Colin/Colin.Liu}
James Colin.Liu Harry Betty

root@pts/1 $ array4=(${array2[*]/Colin/Colin.liu})
root@pts/1 $ echo ${array4[*]}
James Colin.liu Harry Betty

格式:
unset 数组,清除整个数组;
unset 数组[下标],清除单个元素

root@pts/1 $ echo ${array2[*]}
James Colin Harry Betty
root@pts/1 $ echo ${array4[*]}
James Colin.liu Harry Betty

root@pts/1 $ unset array4
root@pts/1 $ unset ${array2[3]}

root@pts/1 $ echo ${array2[*]}
James Colin Harry Betty

root@pts/1 $ echo ${array4[*]}

root@pts/1 $
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