10.25数组练习题

2016-10-25  本文已影响0人  冰凡513

importFoundation

println("Hello, World!")

//有如下一个数组,["type = iOS","Device = iPhone","count = 11344115@163.com","password = 12345"],将其中的内容用“&”符号拼接成一个字符串

letarrary = ["type = iOS","Device = iPhone","count = 11344115@163.com","password = 12345"]

varstr =String()

forvari =0; i

ifi ==arrary.count-1{

str+=arrary[i]

}else{

str+=arrary[i]+"&"

}

}

print(str)

//arrary += & //(自己写的,错误的)

//arrary.insert("&",atIndex: 1)

//arrary.insert("&",atIndex: 3)

//arrary.insert("&",atIndex: 5)

//类名():表示初始化该变量

//定义一个字符串数组,遍历该数组,如果数组中的字符串的长度是4以上并且以“he”开头就将该字符串放到一个新的数组当中

letarrary1 = ["type = iOS","Device = iPhone","count = 11344115@163.com","password = 12345"]

varnewArrary = [String]()//初始化一个元素为字符串的空数组

forelementinarrary1{

if

element.lengthOfBytesUsingEncoding(4)>4&& element.hasPrefix("he"){

newArrary.append(element)

}

}

print(newArrary)

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