C++类成员函数指针

函数指针可以写成return_type (func_name)（args...)，由于类静态函数和全局函数类似，可以用函数指针来调用，对于成员函数，则需要定义成return_type (T::func_name)(args...) [const]

#include <vector>
#include <iostream>
#include <map>
using namespace std;

class MemberFuncTest{
public:
    int add(int a, int b){
        return a + b;
    }

    int dec(int a, int b){
        return a - b;
    }

    int mul(int a, int b){
        return a * b;
    }

    int div(int a, int b){
        return a / b;
    }

    static int test_static(){
        cout<<"I am static func"<<endl;
    }
};

typedef int (MemberFuncTest::*func)(int, int);
map<int, func> func_mp = {{1, &MemberFuncTest::add}, {2,&MemberFuncTest::dec},
                          {3,&MemberFuncTest::mul}, {4, & MemberFuncTest::div}};
//静态成员函数和
typedef int (*func_static)();

int test1(MemberFuncTest m, int a, int b, int type){
    return (m.*func_mp[type])(a, b);
}

int test1(MemberFuncTest* m, int a, int b, int type){
    return (m->*func_mp[type])(a, b);
}

void test2(func_static f){
    f();
}

int main(){
    for(int i = 1;i <= 4; i++){
        cout<<test1( MemberFuncTest(), 6, 2, i)<<" ";
        cout<<test1(new MemberFuncTest(), 6, 2, i)<<endl;
    }
    test2(MemberFuncTest::test_static);
}