ios 获取外网ip
今天在网上找了一个获取外网地址的方法无奈，Data的initcontentsOfURL一直不好使，然后查询了一些资料得到了一个能使用的方法。下面贴代码。
/// 获取外网ip
///
/// - Returns: 外网ip
func getIpinfo() ->String?
{
/** 这是ip查询网址 */
let urlStr = "http://ip.taobao.com/service/getIpInfo.php?ip=myip"
/** 编码为下面转换数据做准备 */
let strEncoding = urlStr.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed)
if strEncoding != nil {
do{
let data = try Data.init(contentsOf: URL.init(string: strEncoding!)!)
do
{
/** 解析data */
if let resultDic = try JSONSerialization.jsonObject(with: data, options: .mutableLeaves) as? [String:Any]
{
/** 打印结果 这边数据比较多类似以下数据 */
/** {
code = 0;
data = {
area = "\U534e\U4e1c";
"area_id" = 300000;
city = "\U4e0a\U6d77\U5e02";
"city_id" = 310100;
country = "\U4e2d\U56fd";
"country_id" = CN;
county = "";
"county_id" = "-1";
ip = "139.226.164.200";
isp = "\U8054\U901a";
"isp_id" = 100026;
region = "\U4e0a\U6d77\U5e02";
"region_id" = 310000;
};
} */
print(resultDic)
/** 用guard逻辑稍微清晰点 */
guard let resultCode = resultDic["code"] as? Int else
{
print("data error")
return nil;
}
guard resultCode == 0 else
{
print("code error")
return nil
}
guard let dataDic = resultDic["data"] as? [String:Any] else
{
print("dic info error")
return nil;
}
guard let ip = dataDic["ip"] as? String else
{
print("ip error")
return nil;
}
/** 得到最终结果 */
return ip
}
}
catch
{
print(error.localizedDescription)
}
}
catch
{
print(error.localizedDescription)
}
}
return nil
}
比较喜欢swift的机制把不确定因素在代码界面排除支持swift
忘了补充下 记得在info.plist文件中加http传输协议许可
