LeetCode 1662. 检查两个字符串数组是否相等

题目

给你两个字符串数组 word1 和 word2 。如果两个数组表示的字符串相同，返回 true ；否则，返回 false 。

数组表示的字符串 是由数组中的所有元素 按顺序 连接形成的字符串。

示例 1：

输入：word1 = ["ab", "c"], word2 = ["a", "bc"]
输出：true
解释：
word1 表示的字符串为 "ab" + "c" -> "abc"
word2 表示的字符串为 "a" + "bc" -> "abc"
两个字符串相同，返回 true
示例 2：

输入：word1 = ["a", "cb"], word2 = ["ab", "c"]
输出：false
示例 3：

输入：word1  = ["abc", "d", "defg"], word2 = ["abcddefg"]
输出：true

提示：

1 <= word1.length, word2.length <= 103
1 <= word1[i].length, word2[i].length <= 103
1 <= sum(word1[i].length), sum(word2[i].length) <= 103
word1[i] 和 word2[i] 由小写字母组成

解题思路

class Solution:
    def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool:
        # 用join，把list转成str
        word1Str = "".join(word1)
        word2Str = "".join(word2)
        return word1Str == word2Str


if __name__ == '__main__':
    word1 = ["ab", "c"]
    word2 = ["a", "bc"]
    word1 = ["a", "cb"]
    word2 = ["ab", "c"]
    ret = Solution().arrayStringsAreEqual(word1, word2)
    print(ret)