iOS企业级开发实用技术

Swift JSON字符串和字典以及数组的互转

2018-12-29  本文已影响1人  强强刘

1、JSONString转换为字典

// JSONString转换为字典
 
func getDictionaryFromJSONString(jsonString:String) ->NSDictionary{
 
    let jsonData:Data = jsonString.data(using: .utf8)!
 
    let dict = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)
    if dict != nil {
        return dict as! NSDictionary
    }
    return NSDictionary()
     
 
}

2、JSONString转换为数组

func getArrayFromJSONString(jsonString:String) ->NSArray{
         
        let jsonData:Data = jsonString.data(using: .utf8)!
         
        let array = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)
        if array != nil {
            return array as! NSArray
        }
        return array as! NSArray
         
    }

3、字典转换为JSONString

/**
     字典转换为JSONString
      
     - parameter dictionary: 字典参数
      
     - returns: JSONString
     */
    func getJSONStringFromDictionary(dictionary:NSDictionary) -> String {
        if (!JSONSerialization.isValidJSONObject(dictionary)) {
            print("无法解析出JSONString")
            return ""
        }
        let data : NSData! = try? JSONSerialization.data(withJSONObject: dictionary, options: []) as NSData!
        let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)
        return JSONString! as String
 
    }

4、数组转换为JSONString

//数组转json
func getJSONStringFromArray(array:NSArray) -> String {
     
    if (!JSONSerialization.isValidJSONObject(array)) {
        print("无法解析出JSONString")
        return ""
    }
     
    let data : NSData! = try? JSONSerialization.data(withJSONObject: array, options: []) as NSData!
    let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)
    return JSONString! as String
     
}
原文链接:https://www.cnblogs.com/jukaiit/p/9345654.html
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