Swift JSON字符串和字典以及数组的互转
2018-12-29 本文已影响1人
强强刘
1、JSONString转换为字典
// JSONString转换为字典
func getDictionaryFromJSONString(jsonString:String) ->NSDictionary{
let jsonData:Data = jsonString.data(using: .utf8)!
let dict = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)
if dict != nil {
return dict as! NSDictionary
}
return NSDictionary()
}
2、JSONString转换为数组
func getArrayFromJSONString(jsonString:String) ->NSArray{
let jsonData:Data = jsonString.data(using: .utf8)!
let array = try? JSONSerialization.jsonObject(with: jsonData, options: .mutableContainers)
if array != nil {
return array as! NSArray
}
return array as! NSArray
}
3、字典转换为JSONString
/**
字典转换为JSONString
- parameter dictionary: 字典参数
- returns: JSONString
*/
func getJSONStringFromDictionary(dictionary:NSDictionary) -> String {
if (!JSONSerialization.isValidJSONObject(dictionary)) {
print("无法解析出JSONString")
return ""
}
let data : NSData! = try? JSONSerialization.data(withJSONObject: dictionary, options: []) as NSData!
let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)
return JSONString! as String
}
4、数组转换为JSONString
//数组转json
func getJSONStringFromArray(array:NSArray) -> String {
if (!JSONSerialization.isValidJSONObject(array)) {
print("无法解析出JSONString")
return ""
}
let data : NSData! = try? JSONSerialization.data(withJSONObject: array, options: []) as NSData!
let JSONString = NSString(data:data as Data,encoding: String.Encoding.utf8.rawValue)
return JSONString! as String
}