iOS 两个数相乘导致 NSDecimalNumber over
2017-10-10 本文已影响123人
zhangyin
先上一段代码,这段代码会导致overflow错误,使APP发生crash:
NSString *priceStr = @"";
NSDecimalNumber *number = [NSDecimalNumber decimalNumberWithString:priceStr];
NSDecimalNumber *countNum = [NSDecimalNumber decimalNumberWithString:stringWithNSInteger(NSIntegerMax)];
number = [number decimalNumberByMultiplyingBy:countNum];
在这段代码中,number的值为:NaN,即:not a number ,非数值;
而countNum 是一个最大的整数,
最后,将NaN和最大的整数相乘,导致了overflow的crash。
解决方案代码如下:
//定义数值处理的行为
NSDecimalNumberHandler *roundUp = [NSDecimalNumberHandler
decimalNumberHandlerWithRoundingMode:NSRoundBankers
scale:2
raiseOnExactness:NO
raiseOnOverflow:NO
raiseOnUnderflow:NO
raiseOnDivideByZero:NO];
NSString *priceStr = @"";
NSDecimalNumber *number = [NSDecimalNumber decimalNumberWithString:priceStr];
NSDecimalNumber *countNum = [NSDecimalNumber decimalNumberWithString:stringWithNSInteger(NSIntegerMax)];
//使用数据处理行为的约定来进行运算,防止crash
number = [number decimalNumberByMultiplyingBy:countNum withBehavior:roundUp];
上面这个例子不会crash了,但是最终number的值为NaN,需要后续的业务逻辑进行判断处理;
NSDecimalNumberHandler 用到的参数,其中:
NSRoundBankers
枚举,截断的方式;完整的定义如下:
// Rounding policies :
// Original
// value 1.2 1.21 1.25 1.35 1.27
// Plain 1.2 1.2 1.3 1.4 1.3
// Down 1.2 1.2 1.2 1.3 1.2
// Up 1.2 1.3 1.3 1.4 1.3
// Bankers 1.2 1.2 1.2 1.4 1.3
typedef NS_ENUM(NSUInteger, NSRoundingMode) {
NSRoundPlain, // Round up on a tie
NSRoundDown, // Always down == truncate
NSRoundUp, // Always up
NSRoundBankers // on a tie round so last digit is even
};
scale
小数点后面的位数(精度)
raiseOnExactness
The exception raised if there is an exactness error.
raiseOnOverflow
是否抛出溢出错误,如果为YES,则APP会捕获溢出错误,这会导致APPcrash;
The exception raised on overflow.
raiseOnUnderflow
The exception raised on underflow.
raiseOnDivideByZero
The exception raised on divide by zero.
补充知识:
-
判断一个数值是否为NaN可以使用系统方法:isnan(x);注:x为数值类型,不是NSDecimalNumber,更不是NSNumber;
-
如果要判断一个NSDecimalNumber 是否为 NAN ,则使用下面的方法:
if([number isEqualToNumber:NSDecimalNumber.notANumber]){
NSLog(@"number is nan");
}else{
NSLog(@"number:%@",number);
}