Scipy练习(5.30作业)
2018-06-01 本文已影响0人
Pessimist_34ad
Ex 10-1
# Ex 10-1
import numpy as np
m = 5
n = 4
A = np.random.rand(m, n)
b = np.random.rand(m, 1)
np.dot(A.T, A)
# Find least square of Ax = b
# Solve ATAx = ATb
x = np.linalg.solve(np.dot(A.T, A), A.T.dot(b))
print(np.linalg.norm(A.dot(x) - b, 2)) # Print the norm of the residual
Finding maximum of f(x) is equivalent to finding the minimum of -f(x).
scipy.optimize.fmin
can be used.
# Ex 10-2
import numpy as np
from scipy import optimize
max_value = optimize.fmin(lambda x: -np.sin(x - 2) ** 2 * np.exp(-x ** 2), 0)
print(max_value[0])
Here's output:
Optimization terminated successfully.
Current function value: -0.911685
Iterations: 20
Function evaluations: 40
0.21625000000000016
scipy.spatial.distance.pdist
is a great function.
# Ex 10-3
import numpy as np
from scipy.spatial.distance import pdist
#Generate a random matrix with n = 5 rows, m = 3 columns
A = np.random.randint(low = 0, high = 10, size= (5, 3))
print(A)
dist = pdist(A)
print(dist)