typeScript学习历程

第五话:函数

2018-02-23  本文已影响10人  小猫吃鱼1990

函数类型

可以为每个参数添加类型,再为函数本身添加返回值类型。

function add(x: number, y: number): number {

    return x + y;

}

let myAdd = function(x: number, y: number): number {

    return x + y;

}

书写完整函数类型

1、以参数列表的形式写出参数类型,为每个参数指定一个名字和类型,名字可以和函数中的参数名字不一致,只要类型匹配即可。

let myAdd: (x: number, y: number) => number = function(x: number, y: number): number {

    return x + y;

}

或者写成这样:

let myAdd: (baseValue: number, increment: number) => number = function(x: number, y: number) {

    return x + y;

}

可选参数和默认参数

1、使用?实现可选参数的功能,可选参数必须跟在必选参数后面。

function buildName(firstName: string, lastName?: string) {

    if (lastName)

        return firstName + " " + lastName;

    else

        return firstName;

}

let result1 = buildName("Bob");  // works correctly now

let result2 = buildName("Bob", "Adams", "Sr.");  // error, too many parameters

let result3 = buildName("Bob", "Adams");  // ah, just right

2、默认初始化值的参数,当用户没有传递这个参数或者传递的值为undefined时,参数为默认值;

    带默认初始化值得参数都是可选的,需跟在必选参数后面。

function buildName(firstName: string, lastName = "Smith") {

    return firstName + " " + lastName;

}

let result1 = buildName("Bob");                  // works correctly now, returns "Bob Smith"

let result2 = buildName("Bob", undefined);      // still works, also returns "Bob Smith"

let result3 = buildName("Bob", "Adams", "Sr.");  // error, too many parameters

let result4 = buildName("Bob", "Adams");        // ah, just right

3、如果带默认初始化值得参数出现在必须参数前面,必须明确的传入undefined值来获取默认值。

functionbuildName(firstName = "Will", lastName:string){

    return firstName + " " + lastName;

}let result1 = buildName("Bob");                  // error, too few parameterslet result2 = buildName("Bob", "Adams", "Sr.");  // error, too many parameterslet result3 = buildName("Bob", "Adams");        // okay and returns "Bob Adams"let result4 = buildName(undefined, "Adams");    // okay and returns "Will Adams"

剩余参数

1、可以把所有参数收集到一个变量里,名字是在(...)后面定的名字。

function buildName(firstName: string, ...restOfName: string[]) {

  return firstName + " " + restOfName.join(" ");

}

let employeeName = buildName("Joseph", "Samuel", "Lucas", "MacKinzie");

2、带有剩余参数的函数类型定义

function buildName(firstName: string, ...restOfName: string[]) {

  return firstName + " " + restOfName.join(" ");

}

let buildNameFun: (fname: string, ...rest: string[]) => string = buildName;

this

1、返回的函数中含有this,最好在函数定义时就制定好this的指向,使用箭头函数,this作为参数。

interface Card {

    suit: string;

    card: number;

}

interface Deck {

    suits: string[];

    cards: number[];

    createCardPicker(this: Deck): () => Card;

}

let deck: Deck = {

    suits: ["hearts", "spades", "clubs", "diamonds"],

    cards: Array(52),

    // NOTE: The function now explicitly specifies that its callee must be of type Deck

    createCardPicker: function(this: Deck) {

        return () => {

            let pickedCard = Math.floor(Math.random() * 52);

            let pickedSuit = Math.floor(pickedCard / 13);

            return {suit: this.suits[pickedSuit], card: pickedCard % 13};

        }

    }

}

let cardPicker = deck.createCardPicker();

let pickedCard = cardPicker();

alert("card: " + pickedCard.card + " of " + pickedCard.suit);

重载

为同一个函数提供多个函数类型定义来进行函数重载。

let suits = ["hearts", "spades", "clubs", "diamonds"];

function pickCard(x: {suit: string; card: number; }[]): number;

function pickCard(x: number): {suit: string; card: number; };

function pickCard(x): any {

    // Check to see if we're working with an object/array

    // if so, they gave us the deck and we'll pick the card

    if (typeof x == "object") {

        let pickedCard = Math.floor(Math.random() * x.length);

        return pickedCard;

    }

    // Otherwise just let them pick the card

    else if (typeof x == "number") {

        let pickedSuit = Math.floor(x / 13);

        return { suit: suits[pickedSuit], card: x % 13 };

    }

}

let myDeck = [{ suit: "diamonds", card: 2 }, { suit: "spades", card: 10 }, { suit: "hearts", card: 4 }];

let pickedCard1 = myDeck[pickCard(myDeck)];

alert("card: " + pickedCard1.card + " of " + pickedCard1.suit);

let pickedCard2 = pickCard(15);

alert("card: " + pickedCard2.card + " of " + pickedCard2.suit);

上一篇下一篇

猜你喜欢

热点阅读