找出与指定值相等的两个数组下标

求数组长度的方法是length = sizeof(num) / sizeof(num[0])//假设是数组num[]

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int num[6],i,j;//假定为6个元素的数组
    int target;
    int length = sizeof(num) / sizeof(num[0]);
    bool find = 0;
    int x1, x2;
    for (i = 0; i < length; i++)
    {
        scanf_s("%d", &num[i]);
    }
    scanf_s("%d", &target);
    for (i = 0; i < length-1; i++)
    {
        for (j = i + 1; j < length; j++)
        {
            if (num[i] + num[j] == target)
            {
                find = 1;
                x1 = i;
                x2 = j;
                break;
            }
        }
    }
    if (find == 1)
    {
        printf("[%d,%d]\n", x1, x2);
    }
    else
    {
        printf("not finid!\n");
    }

    system("pause");
    return 0;
}

输出