解决多个手机连接电脑时，Android adb shell命令使

适用场景

一台电脑连接多台Android手机

效果

1. 单台手机直接连接
2. 多台手机，选择输入，如下：

#/usr/bin/env python/
# -*- coding:utf-8 -*

__author__ = "wdl"
__version__ = "v1.0.1"

import os
import sys
import time

def str_sub(content,num):
    ct = content.replace('[','').replace(']','')
    return ct.split(':')[num].strip()

def get_serialno():
    """
    Objective:解决当多个手机连接电脑，Android adb shell命令使用问题.
    当只有一台手机时，使用adb get-serialno即可获取deviceId.
    """
    phone_brand = []
    serial_num = []

    if os.popen("adb get-state").read() != "device":
        os.popen("adb kill-server")
        os.popen("adb start-server")
        time.sleep(2)
    device_list = os.popen(" adb devices -l").read()

    if "model" not in device_list:
        print("-> Did not detect any Device.")
        sys.exit()
    else:
        serial_num = [sn.split()[0] for sn in device_list.split('\n') if sn and not sn.startswith('List')]
        for sn in serial_num:
            for mi in os.popen("adb -s {0} shell getprop".format(sn)):
                if "ro.build.fingerprint" in mi:
                    model = str_sub(mi,1).split('/')
                    phone_brand.append(model[0])
    devices_info = dict(zip(phone_brand,serial_num))

    if len(devices_info.keys()) > 1:
        print(devices_info)
        deviceId = raw_input(" \n -> Please input mobile brand to connect:")
        return deviceID
    elif len(devices_info.keys()) == 1:
        return devices_info.values()[0]

if __name__ == "__main__":
    print get_serialno()