1140 Look-and-say Sequence(20 分)

2018-08-07  本文已影响0人  zjh3029
#include <iostream>
#include <string>
using namespace std;
int M, N;
int main()
{
    cin >> N >> M;
    string str = to_string(N);
    string str1;
    for (int j = 1; j < M; j++)
    {
        int cnt = 1;
        for (int i=0;i<str.size();i++)
        {
            if(str[i+1]==str[i])
            {
                cnt++;
            }
            else
            {
                str1 += str[i];
                str1 += to_string(cnt);
                cnt = 1;
            }
        }
        str=str1;
        str1.clear();
    }
    cout << str << endl;
    system("pause");
    return 0;
}
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