Collections.sort排序

2018-07-01  本文已影响0人  haiyong6
List<Map<String, Object>> list = new ArrayList<Map<String, Object>>();
            Map<String, Object> map = new HashMap<String, Object>();
            map.put("name", "name1");
            map.put("value", 2);
            list.add(map);
            
            Map<String, Object> map1 = new HashMap<String, Object>();
            map1.put("name", "name2");
            map1.put("value", 16);
            list.add(map1);
            
            Map<String, Object> map2 = new HashMap<String, Object>();
            map2.put("name", "name3");
            map2.put("value", 8);
            list.add(map2);
            
            Collections.sort(list, new Comparator<Map<String, Object>>(){  
                   public int compare(Map<String, Object> v1, Map<String, Object> v2) { 
                       if(Integer.parseInt(v1.get("value").toString()) < Integer.parseInt(v2.get("value").toString())) {
                           return 1;
                       } else if(Integer.parseInt(v1.get("value").toString()) > Integer.parseInt(v2.get("value").toString())) {
                           return -1;
                       } else {
                           return 0;    
                       }
                   }
             });
            
            for(int i = 0; i < list.size(); i++){
                System.out.println(list.get(i).get("name") + " " + list.get(i).get("value"));
            }

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