数据抽样

2020-04-28  本文已影响0人  无敌的肉包

每天抽取 %5

select *
from (
SELECT a ,date
    ,sum(1) over(partition by date) as date_cnt
    ,row_number() over(partition by date order by  md5(a)) as seq
FROM A
) t 
where seq <= round(date_cnt * %5)
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