可选项(Optional)

2019-06-27  本文已影响0人  曹来东

可选项(Optional)

var name: String? = "Jack"
name = nil
var age: Int?//默认就是nil
age = 10
age = nil

var arr = [1,27,19,28]

func get (_ index: Int) -> Int? {
    if index < 0 || index > arr.count {
        return nil
    }
    return arr[index]
}

print(get(1))//Optional(27)
print(get(-1))//nil
print(get(12))//nil

强制解包(Forced Unwrapping)

判断可选项是否包含值

var age: Int?//默认就是nil
age = 10
age = nil

if age != nil {
    print(age!)
}else{
    print("age 为 nil")
}

可选项绑定(Optional Binding)

if let number = Int("123") {
    print("字符串转换整数成功: \(number)")
}else{
    print("字符串转换整数失败")
}

enum Season: String {
    case spring, summer, autumn, winter
}

if let season = Season(rawValue: "3") {
    switch season {
    case .spring:
        print(season.rawValue)
    case .summer:
        print(season.rawValue)
    case .autumn:
        print(season.rawValue)
    case .winter:
        print(season.rawValue)
    }
}else{
    print("无匹配")
}

等价写法

if let first = Int("2") {
    if let second = Int("4") {
        if first < second && first > 0 {
            print("second > first > 0")
        }
    }
}

if let first = Int("2"),let second = Int("4"),first > 0 && first < second {
    print("second > first > 0")
}

While循环中使用可选项绑定

//遍历数组,将所有整数相加
var arr = ["10","20","-2","22","1","c","-2",]

var index = 0
var sum = 0

while let num = Int(arr[index]),num > 0 {
    sum += num
    index += 1
}
print(sum)//30 第三个元素停止

空合运算符??(Nil-Coalescing Operator)

a ?? b

let a: Int? = 10
let b: Int? = 20
let c = a ?? b//a不为nil,b为可选项  返回a. Int? Optional(10)

let a: Int? = 10
let b: Int = 20
let c = a ?? b//a不为nil,b不是可选项  返回a! Int

let a: Int? = nil
let b: Int? = 20
let c = a ?? b//a为nil,b是可选项  返回b . Int? Optional(20)

let a: Int? = nil
let b: Int = 20
let c = a ?? b//a为nil,b不是可选项  返回b.Int

let a: Int? = nil
let b: Int? = nil
let c = a ?? b//a为nil,返回b c = nil Int?

//如果不实用??运算符
let a: Int? = nil
let b: Int = 2
let c: Int
if let tmp = a {
    c = tmp
}else{
    c = b
}

多个 ?? 一起使用

let a: Int? = 1
let b: Int? = 2
let c = a ?? b ?? 3 // a ?? b = a; a ?? 3 = a!;

let a: Int? = nil
let b: Int? = 2
let c = a ?? b ?? 3 // a ?? b = b; b ?? 3 = b!

let a: Int? = nil
let b: Int? = nil
let c = a ?? b ?? 3 // a ?? b = b; b ?? c = 3;

?? 和 if let 配合使用

let a: Int? = nil
let b: Int? = 2

if let c = a ?? b {
    print(c)
}
//等价写法
if a != nil || b != nil {
    
}


if let c = a , let d = b {
    print(c)
    print(d)
}
//等价写法

if a != nil && b != nil {
   let c = a!
   let d = b!
}

guard语句

guard 条件 else {
    //do somrthing
    
    //退出当前作用域
    // return break continue throw error
}
func login(_ info: [String : String]){
    guard let userName = info["userName"] else {
        print("请输入用户名")
        return
        
    }
    guard let passWord = info["passwd"] else {
        print("请输入密码")

        return
        
    }
    
    print(userName,passWord)
}

隐式解包


let num1: Int! = 10
let num2: Int = num1

if num1 != nil {
    print(num2 + 6)
}

if let num3 = num1 {
    print(num3)
}

字符串插值

-消除警告方法

let num1: Int? = 10
print(num1!)
print(num1 ?? 0)
print(String(describing: num1))

多重可选项

var num1: Int? = 10
var num2: Int?? = num1
var num3: Int?? = 10

print(num1 == num2)//true
print(num1 == num3)//true
print(num2 == num3)//true

image.png
(lldb) fr v -R num1
(Swift.Optional<Swift.Int>) num1 = some {
  some = {
    _value = 10
  }
}
(lldb) fr v -R num2
(Swift.Optional<Swift.Optional<Swift.Int>>) num2 = some {
  some = some {
    some = {
      _value = 10
    }
  }
}
(lldb) fr v -R num3
(Swift.Optional<Swift.Optional<Swift.Int>>) num3 = some {
  some = some {
    some = {
      _value = 10
    }
  }
}
(lldb) 
image.png
(lldb) fr v -R num1
(Swift.Optional<Swift.Int>) num1 = none {
  some = {
    _value = 0
  }
}
(lldb) fr v -R num2
(Swift.Optional<Swift.Optional<Swift.Int>>) num2 = some {
  some = none {
    some = {
      _value = 0
    }
  }
}
(lldb) fr v -R num3
(Swift.Optional<Swift.Optional<Swift.Int>>) num3 = none {
  some = some {
    some = {
      _value = 0
    }
  }
}
(lldb) 
Snip20190628_18.png
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