python-数据特征太多时，怎么查找需要的列
2020-07-24 本文已影响0人
丙吉
da_col = list(data.columns)
for i in range(len(da_col)):
pattern1 = re.compile(r'矩形')
m = len(pattern1.findall(da_col[i]))
pattern2 = re.compile(r'速度')
n = len(pattern2.findall(da_col[i]))
if m:
print("*"*12,da_col[i])
if n:
print(da_col[i])
