cannot recognize input near in j

出现这个报错的原因多半出现了子查询形式的情况，比如

select * from (
    select * from table where name = 'zhangsan'
)

重点在于自查询要给一个临时命名，不然就会出现
cannot recognize input near in joinSource

解决：给个临时表名就好了

select * from (
    select * from table where name = 'zhangsan'
)tmp

注：名字随意，不一定叫tmp