lint0005. Kth Largest Element
2019-03-03 本文已影响0人
日光降临
Find K-th largest element in an array.
Example 1:
Input:
n = 1, nums = [1,3,4,2]
Output:
4
Example 2:
Input:
n = 3, nums = [9,3,2,4,8]
Output:
4
Challenge
O(n) time, O(1) extra memory.
class Solution {
/*
* @param k : description of k
* @param nums : array of nums
* @return: description of return
*/
public int kthLargestElement(int k, int[] nums) {
if (nums == null || nums.length == 0 || k < 1 || k > nums.length){
return -1;
}
return partition(nums, 0, nums.length - 1, nums.length - k);
}
private int partition(int[] nums, int start, int end, int k) {
if (start >= end) {
return nums[k];
}
int left = start, right = end;
int pivot = nums[(start + end) / 2];
while (left <= right) {
while (left <= right && nums[left] < pivot) {
left++;
}
while (left <= right && nums[right] > pivot) {
right--;
}
if (left <= right) {
swap(nums, left, right);
left++;
right--;
}
}
if (k <= right) {
return partition(nums, start, right, k);
}
if (k >= left) {
return partition(nums, left, end, k);
}
return nums[k];
}
private void swap(int[] nums, int i, int j) {
int tmp = nums[i];
nums[i] = nums[j];
nums[j] = tmp;
}
};
class Solution {
/*
* @param k : description of k
* @param nums : array of nums
* @return: description of return
*/
public int kthLargestElement(int k, int[] nums) {
// write your code here
int low = 0, high = nums.length -1;
while(low <= high){
int index = low-1;
for(int i = low; i < high; i++){
if(nums[i] > nums[high]){
swap(nums, i, ++index);
}
}
swap(nums, ++index, high);
if(index == k - 1){
return nums[index];
}
if(index < k -1){
low = index + 1;
}else{
high = index - 1;
}
}
return -1;
}
private void swap(int[] nums, int a, int b){
int temp = nums[a];
nums[a] = nums[b];
nums[b] = temp;
}
};