PHP取不定个数数组交集

2018-07-27  本文已影响0人  willeny

最近有个需求,有一个N个二维数组,N是动态的,不固定个数,现需取这N个数组的交集内容。

    $result_arr = array_intersect_assoc($arr_sourse[0],$arr_sourse[1],.......$arr_sourse[N-1]);
    $arr1 = ["16","2","3","6","9","17"];
    $arr2 = ["16","2","3","9","15"];
    $arr3 = ["16","2","3","6","8","17"];

固定数组的用法

    $diff = array_intersect($arr1,$arr2,$arr3);
    echo '<pre>';
    print_r($diff);// ["16","2","3"]

不固定数组用法

    $result_array = call_user_func_array ('array_intersect_assoc', array($arr1, $arr2,$arr3));
    echo '<pre>';
    print_r($result_array);// ["16","2","3"]
上一篇 下一篇

猜你喜欢

热点阅读