02_从前序与中序遍历序列构造二叉树

2019-11-12  本文已影响0人  butters001
# Definition for a binary tree node.
class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None


class Solution(object):
    def buildTree(self, preorder, inorder):
        """
        :type preorder: List[int]
        :type inorder: List[int]
        :rtype: TreeNode
        """
        if not preorder or not inorder:
            return
        root = TreeNode(preorder[0])
        root_index = inorder.index(preorder[0])
        root.left = self.buildTree(preorder[1:root_index+1], inorder[:root_index])
        root.right = self.buildTree(preorder[root_index+1:], inorder[root_index+1:])
        return root

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