02_从前序与中序遍历序列构造二叉树
2019-11-12 本文已影响0人
butters001
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def buildTree(self, preorder, inorder):
"""
:type preorder: List[int]
:type inorder: List[int]
:rtype: TreeNode
"""
if not preorder or not inorder:
return
root = TreeNode(preorder[0])
root_index = inorder.index(preorder[0])
root.left = self.buildTree(preorder[1:root_index+1], inorder[:root_index])
root.right = self.buildTree(preorder[root_index+1:], inorder[root_index+1:])
return root