摘录JDBC实现XA事务原理代码
2018-11-02 本文已影响0人
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import com.mysql.jdbc.jdbc2.optional.MysqlXAConnection;
import com.mysql.jdbc.jdbc2.optional.MysqlXid;
import javax.sql.XAConnection;
import javax.transaction.xa.XAException;
import javax.transaction.xa.XAResource;
import javax.transaction.xa.Xid;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;
public class MysqlXAConnectionTest {
public static void main(String[] args) throws SQLException {
//true表示打印XA语句,,用于调试
boolean logXaCommands = true;
// 获得资源管理器操作接口实例 RM1
Connection conn1 = DriverManager.getConnection("jdbc:mysql://localhost:3306/test", "root", "shxx12151022");
XAConnection xaConn1 = new MysqlXAConnection((com.mysql.jdbc.Connection) conn1, logXaCommands);
XAResource rm1 = xaConn1.getXAResource();
// 获得资源管理器操作接口实例 RM2
Connection conn2 = DriverManager.getConnection("jdbc:mysql://localhost:3306/test", "root",
"shxx12151022");
XAConnection xaConn2 = new MysqlXAConnection((com.mysql.jdbc.Connection) conn2, logXaCommands);
XAResource rm2 = xaConn2.getXAResource();
// AP请求TM执行一个分布式事务,TM生成全局事务id
byte[] gtrid = "g12345".getBytes();
int formatId = 1;
try {
// ==============分别执行RM1和RM2上的事务分支====================
// TM生成rm1上的事务分支id
byte[] bqual1 = "b00001".getBytes();
Xid xid1 = new MysqlXid(gtrid, bqual1, formatId);
// 执行rm1上的事务分支
rm1.start(xid1, XAResource.TMNOFLAGS);//One of TMNOFLAGS, TMJOIN, or TMRESUME.
PreparedStatement ps1 = conn1.prepareStatement("INSERT into user(name) VALUES ('tianshouzhi')");
ps1.execute();
rm1.end(xid1, XAResource.TMSUCCESS);
// TM生成rm2上的事务分支id
byte[] bqual2 = "b00002".getBytes();
Xid xid2 = new MysqlXid(gtrid, bqual2, formatId);
// 执行rm2上的事务分支
rm2.start(xid2, XAResource.TMNOFLAGS);
PreparedStatement ps2 = conn2.prepareStatement("INSERT into user(name) VALUES ('wangxiaoxiao')");
ps2.execute();
rm2.end(xid2, XAResource.TMSUCCESS);
// ===================两阶段提交================================
// phase1:询问所有的RM 准备提交事务分支
int rm1_prepare = rm1.prepare(xid1);
int rm2_prepare = rm2.prepare(xid2);
// phase2:提交所有事务分支
boolean onePhase = false; //TM判断有2个事务分支,所以不能优化为一阶段提交
if (rm1_prepare == XAResource.XA_OK
&& rm2_prepare == XAResource.XA_OK
) {//所有事务分支都prepare成功,提交所有事务分支
rm1.commit(xid1, onePhase);
rm2.commit(xid2, onePhase);
} else {//如果有事务分支没有成功,则回滚
rm1.rollback(xid1);
rm1.rollback(xid2);
}
} catch (XAException e) {
// 如果出现异常,也要进行回滚
e.printStackTrace();
}
}
}